Optimal. Leaf size=292 \[ \frac{10 b^2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3}{e^6 (a+b x) (d+e x)}-\frac{5 b \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^4}{2 e^6 (a+b x) (d+e x)^2}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^5}{3 e^6 (a+b x) (d+e x)^3}+\frac{b^5 x^2 \sqrt{a^2+2 a b x+b^2 x^2}}{2 e^4 (a+b x)}-\frac{b^4 x \sqrt{a^2+2 a b x+b^2 x^2} (4 b d-5 a e)}{e^5 (a+b x)}+\frac{10 b^3 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^2 \log (d+e x)}{e^6 (a+b x)} \]
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Rubi [A] time = 0.432272, antiderivative size = 292, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.071 \[ \frac{10 b^2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3}{e^6 (a+b x) (d+e x)}-\frac{5 b \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^4}{2 e^6 (a+b x) (d+e x)^2}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^5}{3 e^6 (a+b x) (d+e x)^3}+\frac{b^5 x^2 \sqrt{a^2+2 a b x+b^2 x^2}}{2 e^4 (a+b x)}-\frac{b^4 x \sqrt{a^2+2 a b x+b^2 x^2} (4 b d-5 a e)}{e^5 (a+b x)}+\frac{10 b^3 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^2 \log (d+e x)}{e^6 (a+b x)} \]
Antiderivative was successfully verified.
[In] Int[(a^2 + 2*a*b*x + b^2*x^2)^(5/2)/(d + e*x)^4,x]
[Out]
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Rubi in Sympy [A] time = 35.6132, size = 231, normalized size = 0.79 \[ \frac{5 b^{3} \left (3 a + 3 b x\right ) \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{3 e^{4}} + \frac{10 b^{3} \left (a e - b d\right ) \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{e^{5}} + \frac{10 b^{3} \left (a e - b d\right )^{2} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}} \log{\left (d + e x \right )}}{e^{6} \left (a + b x\right )} - \frac{10 b^{2} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}}{3 e^{3} \left (d + e x\right )} - \frac{b \left (5 a + 5 b x\right ) \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}}{6 e^{2} \left (d + e x\right )^{2}} - \frac{\left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{5}{2}}}{3 e \left (d + e x\right )^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b**2*x**2+2*a*b*x+a**2)**(5/2)/(e*x+d)**4,x)
[Out]
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Mathematica [A] time = 0.224213, size = 247, normalized size = 0.85 \[ \frac{\sqrt{(a+b x)^2} \left (-2 a^5 e^5-5 a^4 b e^4 (d+3 e x)-20 a^3 b^2 e^3 \left (d^2+3 d e x+3 e^2 x^2\right )+10 a^2 b^3 d e^2 \left (11 d^2+27 d e x+18 e^2 x^2\right )+10 a b^4 e \left (-13 d^4-27 d^3 e x-9 d^2 e^2 x^2+9 d e^3 x^3+3 e^4 x^4\right )+60 b^3 (d+e x)^3 (b d-a e)^2 \log (d+e x)+b^5 \left (47 d^5+81 d^4 e x-9 d^3 e^2 x^2-63 d^2 e^3 x^3-15 d e^4 x^4+3 e^5 x^5\right )\right )}{6 e^6 (a+b x) (d+e x)^3} \]
Antiderivative was successfully verified.
[In] Integrate[(a^2 + 2*a*b*x + b^2*x^2)^(5/2)/(d + e*x)^4,x]
[Out]
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Maple [B] time = 0.025, size = 502, normalized size = 1.7 \[{\frac{60\,\ln \left ( ex+d \right ){x}^{3}{a}^{2}{b}^{3}{e}^{5}+60\,\ln \left ( ex+d \right ){x}^{3}{b}^{5}{d}^{2}{e}^{3}+180\,\ln \left ( ex+d \right ) x{b}^{5}{d}^{4}e+110\,{a}^{2}{b}^{3}{d}^{3}{e}^{2}-2\,{a}^{5}{e}^{5}+47\,{b}^{5}{d}^{5}-360\,\ln \left ( ex+d \right ){x}^{2}a{b}^{4}{d}^{2}{e}^{3}+180\,\ln \left ( ex+d \right ){x}^{2}{a}^{2}{b}^{3}d{e}^{4}-120\,\ln \left ( ex+d \right ){x}^{3}a{b}^{4}d{e}^{4}+180\,\ln \left ( ex+d \right ){x}^{2}{b}^{5}{d}^{3}{e}^{2}+180\,\ln \left ( ex+d \right ) x{a}^{2}{b}^{3}{d}^{2}{e}^{3}-360\,\ln \left ( ex+d \right ) xa{b}^{4}{d}^{3}{e}^{2}+60\,\ln \left ( ex+d \right ){b}^{5}{d}^{5}+30\,{x}^{4}a{b}^{4}{e}^{5}-15\,{x}^{4}{b}^{5}d{e}^{4}-63\,{x}^{3}{b}^{5}{d}^{2}{e}^{3}-60\,{x}^{2}{a}^{3}{b}^{2}{e}^{5}-9\,{x}^{2}{b}^{5}{d}^{3}{e}^{2}-15\,x{a}^{4}b{e}^{5}+81\,x{b}^{5}{d}^{4}e-5\,{a}^{4}bd{e}^{4}-20\,{a}^{3}{b}^{2}{d}^{2}{e}^{3}-130\,a{b}^{4}{d}^{4}e+90\,{x}^{3}a{b}^{4}d{e}^{4}+180\,{x}^{2}{a}^{2}{b}^{3}d{e}^{4}-90\,{x}^{2}a{b}^{4}{d}^{2}{e}^{3}+60\,\ln \left ( ex+d \right ){a}^{2}{b}^{3}{d}^{3}{e}^{2}-120\,\ln \left ( ex+d \right ) a{b}^{4}{d}^{4}e-60\,x{a}^{3}{b}^{2}d{e}^{4}+270\,x{a}^{2}{b}^{3}{d}^{2}{e}^{3}+3\,{x}^{5}{b}^{5}{e}^{5}-270\,xa{b}^{4}{d}^{3}{e}^{2}}{6\, \left ( bx+a \right ) ^{5}{e}^{6} \left ( ex+d \right ) ^{3}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{{\frac{5}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b^2*x^2+2*a*b*x+a^2)^(5/2)/(e*x+d)^4,x)
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(5/2)/(e*x + d)^4,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.211862, size = 574, normalized size = 1.97 \[ \frac{3 \, b^{5} e^{5} x^{5} + 47 \, b^{5} d^{5} - 130 \, a b^{4} d^{4} e + 110 \, a^{2} b^{3} d^{3} e^{2} - 20 \, a^{3} b^{2} d^{2} e^{3} - 5 \, a^{4} b d e^{4} - 2 \, a^{5} e^{5} - 15 \,{\left (b^{5} d e^{4} - 2 \, a b^{4} e^{5}\right )} x^{4} - 9 \,{\left (7 \, b^{5} d^{2} e^{3} - 10 \, a b^{4} d e^{4}\right )} x^{3} - 3 \,{\left (3 \, b^{5} d^{3} e^{2} + 30 \, a b^{4} d^{2} e^{3} - 60 \, a^{2} b^{3} d e^{4} + 20 \, a^{3} b^{2} e^{5}\right )} x^{2} + 3 \,{\left (27 \, b^{5} d^{4} e - 90 \, a b^{4} d^{3} e^{2} + 90 \, a^{2} b^{3} d^{2} e^{3} - 20 \, a^{3} b^{2} d e^{4} - 5 \, a^{4} b e^{5}\right )} x + 60 \,{\left (b^{5} d^{5} - 2 \, a b^{4} d^{4} e + a^{2} b^{3} d^{3} e^{2} +{\left (b^{5} d^{2} e^{3} - 2 \, a b^{4} d e^{4} + a^{2} b^{3} e^{5}\right )} x^{3} + 3 \,{\left (b^{5} d^{3} e^{2} - 2 \, a b^{4} d^{2} e^{3} + a^{2} b^{3} d e^{4}\right )} x^{2} + 3 \,{\left (b^{5} d^{4} e - 2 \, a b^{4} d^{3} e^{2} + a^{2} b^{3} d^{2} e^{3}\right )} x\right )} \log \left (e x + d\right )}{6 \,{\left (e^{9} x^{3} + 3 \, d e^{8} x^{2} + 3 \, d^{2} e^{7} x + d^{3} e^{6}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(5/2)/(e*x + d)^4,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b**2*x**2+2*a*b*x+a**2)**(5/2)/(e*x+d)**4,x)
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GIAC/XCAS [A] time = 0.223325, size = 506, normalized size = 1.73 \[ 10 \,{\left (b^{5} d^{2}{\rm sign}\left (b x + a\right ) - 2 \, a b^{4} d e{\rm sign}\left (b x + a\right ) + a^{2} b^{3} e^{2}{\rm sign}\left (b x + a\right )\right )} e^{\left (-6\right )}{\rm ln}\left ({\left | x e + d \right |}\right ) + \frac{1}{2} \,{\left (b^{5} x^{2} e^{4}{\rm sign}\left (b x + a\right ) - 8 \, b^{5} d x e^{3}{\rm sign}\left (b x + a\right ) + 10 \, a b^{4} x e^{4}{\rm sign}\left (b x + a\right )\right )} e^{\left (-8\right )} + \frac{{\left (47 \, b^{5} d^{5}{\rm sign}\left (b x + a\right ) - 130 \, a b^{4} d^{4} e{\rm sign}\left (b x + a\right ) + 110 \, a^{2} b^{3} d^{3} e^{2}{\rm sign}\left (b x + a\right ) - 20 \, a^{3} b^{2} d^{2} e^{3}{\rm sign}\left (b x + a\right ) - 5 \, a^{4} b d e^{4}{\rm sign}\left (b x + a\right ) - 2 \, a^{5} e^{5}{\rm sign}\left (b x + a\right ) + 60 \,{\left (b^{5} d^{3} e^{2}{\rm sign}\left (b x + a\right ) - 3 \, a b^{4} d^{2} e^{3}{\rm sign}\left (b x + a\right ) + 3 \, a^{2} b^{3} d e^{4}{\rm sign}\left (b x + a\right ) - a^{3} b^{2} e^{5}{\rm sign}\left (b x + a\right )\right )} x^{2} + 15 \,{\left (7 \, b^{5} d^{4} e{\rm sign}\left (b x + a\right ) - 20 \, a b^{4} d^{3} e^{2}{\rm sign}\left (b x + a\right ) + 18 \, a^{2} b^{3} d^{2} e^{3}{\rm sign}\left (b x + a\right ) - 4 \, a^{3} b^{2} d e^{4}{\rm sign}\left (b x + a\right ) - a^{4} b e^{5}{\rm sign}\left (b x + a\right )\right )} x\right )} e^{\left (-6\right )}}{6 \,{\left (x e + d\right )}^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(5/2)/(e*x + d)^4,x, algorithm="giac")
[Out]